The major product Z obtained in the following | vedclass

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(B) $1$. The starting material is $m$-bromoaniline. Treatment with $NaNO_2/HCl$ at $273-278 \ K$ performs diazotization to form $m$-bromobenzenediazon

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$1,3-$dibromo$-4-$nitrobenzene

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(B) $1$. The starting material is $m$-bromoaniline. Treatment with $NaNO_2/HCl$ at $273-278 \ K$ performs diazotization to form $m$-bromobenzenediazonium chloride $(X)$.$2$. Reaction of $X$ with $Cu_2Br_2$ (Sandmeyer reaction) replaces the diazonium group with a bromine atom,yielding $1,3$-dibromobenzene $(Y)$.$3$. Finally,nitration of $1,3$-dibromobenzene using $HNO_3/H_2SO_4$ occurs. Since the bromine atom is ortho/para-directing,the nitro group enters the position ortho to one bromine and para to the other,which is the $4$-position relative to one of the bromine atoms,leading to $1,3$-dibromo$-4-$nitrobenzene as the major product.

The major product $Z$ obtained in the following reaction scheme is

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The major product $(R)$ of the following reaction is:
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What are $X$ and $Y$?

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