The major product 'A' of the following given | vedclass

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(D) The reaction involves the acid-catalyzed cyclization of $2,7-	ext{dimethyl}-2,6-	ext{octadiene}$.First,the protonation of one of the double bond

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(D) The reaction involves the acid-catalyzed cyclization of $2,7-	ext{dimethyl}-2,6-	ext{octadiene}$.First,the protonation of one of the double bonds forms a tertiary carbocation.Then,an internal nucleophilic attack by the other double bond occurs,leading to the formation of a five-membered ring with a tertiary carbocation.Finally,the loss of a proton $(-H^{+})$ from the carbocation results in the formation of the major product,which is $1,1,2-	ext{trimethyl}-2-	ext{isopropylidenecyclopentane}$ (or a similar isomer depending on the specific mechanism path).Looking at the final structure shown in the mechanism: the product is $1,1-	ext{dimethyl}-2-	ext{isopropylidenecyclopentane}$.In this structure,the double bond is between the ring carbon and the isopropylidene carbon.This double bond involves $2$ carbon atoms,both of which are $sp^2$ hybridized.Therefore,the major product has $2$ $sp^2$ hybridized carbon atoms.

The major product $'A'$ of the following given reaction has $......\,sp^2$ hybridized carbon atoms.
$2,7-\text{Dimethyl}-2,6-\text{octadiene} \xrightarrow{H^{+}} A \text{ (Major Product)}$

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The major product $'A'$ of the following given reaction has $......\,sp^2$ hybridized carbon atoms.$2,7-\text{Dimethyl}-2,6-\text{octadiene} \xrightarrow{H^{+}} A \text{ (Major Product)}$