The major product formed in the dehydrohaloge | vedclass

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(A) The correct answer is $(A)$. According to $Saytzeff's \ Rule$,in dehydrohalogenation reactions,the major product is the more highly substituted al

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$Saytzeff's \ Rule$

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(A) The correct answer is $(A)$. According to $Saytzeff's \ Rule$,in dehydrohalogenation reactions,the major product is the more highly substituted alkene,which is the one with more alkyl groups attached to the double-bonded carbons. For $2-Bromopentane$,the elimination of $HBr$ can yield either $Pent-1-ene$ or $Pent-2-ene$. $Pent-2-ene$ is a disubstituted alkene,whereas $Pent-1-ene$ is a monosubstituted alkene. Therefore,$Pent-2-ene$ is the more stable and major product.

The major product formed in the dehydrohalogenation reaction of $2-Bromopentane$ is $Pent-2-ene$. This product formation is based on?

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