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(C) The reaction involves the alkylation of adenine with $CH_3I$ in the presence of a base. The base deprotonates the nitrogen atom at the $N-9$ posit

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(C) The reaction involves the alkylation of adenine with $CH_3I$ in the presence of a base. The base deprotonates the nitrogen atom at the $N-9$ position (marked with $*$ in the mechanism),which is the most acidic site in the adenine molecule. This deprotonated nitrogen then acts as a nucleophile and attacks the methyl group of $CH_3I$ via an $S_N2$ mechanism,resulting in the formation of $9-methyladenine$ as the major product.

The major product in the following reaction is

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