The major products Y and Z in the following r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Electrophilic aromatic substitution of $3$-methyl-$4$-hydroxybenzaldehyde with $Br_2/Fe$ occurs at the position ortho to the $-OH$ group

Vedclass · Accepted Answer

Vedclass · Answer

(B) Step $1$: Electrophilic aromatic substitution of $3$-methyl-$4$-hydroxybenzaldehyde with $Br_2/Fe$ occurs at the position ortho to the $-OH$ group. The $-OH$ group is a strong activating group,directing the incoming electrophile $Br^+$ to the ortho position. This yields $X$ ($3$-bromo-$4$-methyl-$5$-hydroxybenzaldehyde).Step $2$: The compound $X$ undergoes the Cannizzaro reaction with concentrated $KOH$ followed by acid workup $(H_3O^+)$. The aldehyde group $(-CHO)$ is converted into a mixture of alcohol $(-CH_2OH)$ and carboxylic acid $(-COOH)$ groups. The resulting products $Y$ and $Z$ are $3$-bromo-$4$-methyl-$5$-hydroxybenzyl alcohol and $3$-bromo-$4$-methyl-$5$-hydroxybenzoic acid,respectively.

The major products $Y$ and $Z$ in the following reactions are

Similar Questions

The treatment of $Ph_2C(OH)CH_2NH_2$ with $NaNO_2 - HCl$ gives a product $(P)$ which on oxidation gives benzoic acid only. Identify the product $(P)$.

When $m$-chlorobenzaldehyde is treated with $50\%$ $KOH$ solution,the product$(s)$ obtained is (are):

Which one of the following compounds does not give a primary alcohol on reduction?

$2CD_2=O + OH^- \xrightarrow{\quad} X + Y$ ($Y$ is an alcohol and $D$ is deuterium). Identify $X$ and $Y$.

Which is correct about vanillin?

Vedclass Test Series

Exam Paper Generator

Online Exam Module