The major products $P$ and $Q$ formed in the following reactions of benzonitrile are

Consider the following reaction sequence starting from $p$-nitrotoluene:
$(i)$ $\text{Sn/HCl; OH}^-$
(ii) $(\text{CH}_3\text{CO})_2\text{O}$
(iii) $\text{Br}_2/\text{AlBr}_3$
(iv) $\text{H}_3\text{O}^+$
When the final product $(P)$ is subjected to Carius analysis using $\text{AgNO}_3$, $1.0 \text{ g}$ of the product $(P)$ will produce . . . . . . $\text{g}$ of the precipitate of $\text{AgBr}$. (Nearest Integer)
(Given: molar mass in $\text{g mol}^{-1}$: $\text{C} = 12, \text{H} = 1, \text{O} = 16, \text{N} = 14, \text{Br} = 80, \text{Ag} = 108$)

Among the compounds given below,the order of basicity is:
$(I)$ Piperidine
$(II)$ Pyridine
$(III)$ Morpholine
$(IV)$ Pyrrole

Match the following:

List-$I$ (Amine)	List-$II$ ($pK_b$ value)
$A$. $N,N$-Dimethylaniline	$I$. $9.30$
$B$. Aniline	$II$. $8.92$
$C$. $N$-Ethylethanamine	$III$. $9.38$
$D$. $N$-Methylaniline	$IV$. $3.00$

The correct answer is

$NBS \xrightarrow{KOBr} (A)$. The product $(A)$ is:

An organic compound $A$ contains nitrogen and chlorine. It dissolves readily in water to give a solution that turns litmus red. Titration of compound $A$ with standard base indicates that the molecular weight of $A$ is $131 \pm 2$. When a sample of $A$ is treated with aqueous $NaOH$,a liquid separates which contains $N$ but not $Cl$. Treatment of the obtained liquid with nitrous acid followed by phenol gives an orange precipitate. The compound $A$ is: