The mass of benzanilide obtained from the ben | vedclass

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(B) The reaction is: $C_6H_5NH_2 + C_6H_5COCl ightarrow C_6H_5NHCOC_6H_5 + HCl$Molar mass of aniline $(C_6H_5NH_2)$ = $6 	imes 12 + 7 	imes 1 + 14

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$10$

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(B) The reaction is: $C_6H_5NH_2 + C_6H_5COCl ightarrow C_6H_5NHCOC_6H_5 + HCl$Molar mass of aniline $(C_6H_5NH_2)$ = $6 	imes 12 + 7 	imes 1 + 14 = 93 \ g \ mol^{-1}$.Molar mass of benzanilide $(C_6H_5NHCOC_6H_5)$ = $13 	imes 12 + 11 	imes 1 + 14 + 16 = 197 \ g \ mol^{-1}$.Moles of aniline = $\frac{5.8 \ g}{93 \ g \ mol^{-1}} \approx 0.06237 \ mol$.Theoretical moles of benzanilide = $0.06237 \ mol$.Actual moles of benzanilide = $0.06237 	imes 0.82 \approx 0.05114 \ mol$.Mass of benzanilide = $0.05114 \ mol 	imes 197 \ g \ mol^{-1} \approx 10.07 \ g$.Rounding to the nearest integer, the mass is $10 \ g$.

The mass of benzanilide obtained from the benzoylation reaction of $5.8 \ g$ of aniline, if the yield of product is $82\%$, is . . . . . . $g$ (nearest integer).
(Given molar mass in $g \ mol^{-1}$: $H: 1, C: 12, N: 14, O: 16$)

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The mass of benzanilide obtained from the benzoylation reaction of $5.8 \ g$ of aniline, if the yield of product is $82\%$, is . . . . . . $g$ (nearest integer).(Given molar mass in $g \ mol^{-1}$: $H: 1, C: 12, N: 14, O: 16$)