The masses of three wires of copper are in th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The resistance of a wire is given by $R = \rho \frac{l}{A}$.Since the mass $m = A \cdot l \cdot d$ (where $d$ is density),we have $A = \frac{m}{l

Vedclass · Accepted Answer

$125 : 15 : 1$

Vedclass · Answer

(D) The resistance of a wire is given by $R = \rho \frac{l}{A}$.Since the mass $m = A \cdot l \cdot d$ (where $d$ is density),we have $A = \frac{m}{l \cdot d}$.Substituting $A$ into the resistance formula: $R = \rho \frac{l^2 \cdot d}{m}$.Since $\rho$ and $d$ are constant for copper,$R \propto \frac{l^2}{m}$.Given the ratios $m_1 : m_2 : m_3 = 1 : 3 : 5$ and $l_1 : l_2 : l_3 = 5 : 3 : 1$,we calculate the ratio of resistances:$R_1 : R_2 : R_3 = \frac{5^2}{1} : \frac{3^2}{3} : \frac{1^2}{5} = 25 : 3 : 0.2$.To express this in integers,multiply by $5$:$R_1 : R_2 : R_3 = 125 : 15 : 1$.

The masses of three wires of copper are in the ratio of $1 : 3 : 5$ and their lengths are in the ratio $5 : 3 : 1.$ The ratio of their electrical resistances is

Similar Questions

Describe the effect of temperature on the electrical resistance of metals and semiconductors.

Two wires are made of two different materials whose specific resistances are in the ratio $2:3$,lengths are in the ratio $3:4$,and cross-sectional areas are in the ratio $4:5$. The ratio of their resistances is:

If the masses of three wires of same material are in the ratio of $1: 2: 3$ and their lengths are in the ratio of $3: 2: 1$,then electrical resistances of these wires are in the ratio

The length of a hollow tube is $5\,m$,its outer diameter is $10\,cm$,and the thickness of its wall is $5\,mm$. If the resistivity of the material of the tube is $1.7 \times 10^{-8} \,\Omega m$,then the resistance of the tube will be:

Wires $P$ and $Q$ have the same resistance at room temperature. When heated,the resistance of $P$ increases and that of $Q$ decreases. We conclude that:

Vedclass Test Series

Exam Paper Generator

Online Exam Module