The mathematical form of Charles's law is given by $V_{t} = V_{0} \left( \frac{273.15 + t}{273.15} \right)$. Using this equation,explain the relationship between volume $(V)$ and temperature $(T)$ in Kelvin.

(N/A) The given equation is $V_{t} = V_{0} \left( \frac{273.15 + t}{273.15} \right)$.
Let $T = 273.15 + t$,where $T$ is the temperature in Kelvin and $t$ is the temperature in degrees Celsius.
Substituting this into the equation,we get $V_{t} = V_{0} \left( \frac{T}{273.15} \right)$.
This can be rewritten as $V_{t} = \left( \frac{V_{0}}{273.15} \right) T$.
Since $V_{0}$ and $273.15$ are constants,we can write $V_{t} = k T$,where $k = \frac{V_{0}}{273.15}$.
This shows that volume $(V)$ is directly proportional to temperature $(T)$ in Kelvin,which is the definition of Charles's law.
The graph of $V$ versus $T$ (in Kelvin) is a straight line passing through the origin with a slope of $\frac{V_{0}}{273.15}$.