The maximum energy in the thermal radiation f | vedclass

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(C) According to Wien's displacement law, $\lambda_{m} T = 	ext{constant}$, where $\lambda_{m}$ is the wavelength corresponding to maximum energy and

Vedclass · Accepted Answer

$0.5$

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(C) According to Wien's displacement law, $\lambda_{m} T = 	ext{constant}$, where $\lambda_{m}$ is the wavelength corresponding to maximum energy and $T$ is the absolute temperature.Therefore, $\lambda_{1} T_{1} = \lambda_{2} T_{2}$.Given $\lambda_{1} = 11 	imes 10^{-5} \ cm$ and $\lambda_{2} = 5.5 	imes 10^{-5} \ cm$.We are given $T_{1} = n T_{2}$.Substituting the values into the equation: $(11 	imes 10^{-5}) 	imes (n T_{2}) = (5.5 	imes 10^{-5}) 	imes T_{2}$.$n = \frac{5.5 	imes 10^{-5}}{11 	imes 10^{-5}} = \frac{5.5}{11} = 0.5$.

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