The maximum number of isomers (including stereoisomers) that are possible on monochlorination of the following compound is:

  • A
    $7$
  • B
    $8$
  • C
    $9$
  • D
    $1$

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An alkane $(Y)$ requires $8$ moles of oxygen for complete combustion and on chlorination with $Cl_2/h\nu$, $(Y)$ gives only one monochlorinated product $(Z)$. The total number of primary carbon atoms in $(Y)$ is . . . . . . .

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