The maximum number of possible interference m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The condition for interference maxima in Young's double-slit experiment is given by $\Delta x = d \sin 	heta = n \lambda$,where $n$ is an integer

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) The condition for interference maxima in Young's double-slit experiment is given by $\Delta x = d \sin 	heta = n \lambda$,where $n$ is an integer.Given that the slit separation $d = 2 \lambda$,we substitute this into the equation:$2 \lambda \sin 	heta = n \lambda$$2 \sin 	heta = n$$\sin 	heta = \frac{n}{2}$Since the maximum value of $\sin 	heta$ is $1$,we have $-1 \le \frac{n}{2} \le 1$,which implies $-2 \le n \le 2$.The possible integer values for $n$ are $-2, -1, 0, 1, 2$.Counting these values,we get a total of $5$ interference maxima.

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double-slit experiment is:

Similar Questions

In $\triangle ABC$,if $\frac{1}{b+c} + \frac{1}{c+a} = \frac{3}{a+b+c}$,then $C$ is equal to (in $^{\circ}$)

The solution of the differential equation $\frac{dy}{dx} = \frac{x - y + 3}{2(x - y) + 5}$ is

Which organisms are primarily included as pests?

Let $f(0)=1, f(0.5)=\frac{5}{4}, f(1)=2, f(1.5)=\frac{13}{4}$ and $f(2)=5$. Using Simpson's rule,$\int_0^2 f(x) dx$ is equal to

Out of $13$ cricket players,$4$ are bowlers. In how many ways can a cricket team of $11$ players be formed such that at least $2$ bowlers are included?

Vedclass Test Series

Exam Paper Generator

Online Exam Module