The mean deviation about the mean for the dat | vedclass

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(B) Step $1$: Calculate the mean $(\mu)$ of the data.$\mu = \frac{4+7+8+9+10+12+13+17}{8} = \frac{80}{8} = 10$.Step $2$: Calculate the mean deviation

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$3$

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(B) Step $1$: Calculate the mean $(\mu)$ of the data.$\mu = \frac{4+7+8+9+10+12+13+17}{8} = \frac{80}{8} = 10$.Step $2$: Calculate the mean deviation about the mean using the formula $\frac{1}{N} \sum |x_i - \mu|$.$|4-10| = 6$$|7-10| = 3$$|8-10| = 2$$|9-10| = 1$$|10-10| = 0$$|12-10| = 2$$|13-10| = 3$$|17-10| = 7$Sum of absolute deviations $= 6+3+2+1+0+2+3+7 = 24$.Mean deviation $= \frac{24}{8} = 3$.

Class interval	$0-4$	$4-8$	$8-12$	$12-16$	$16-20$
Frequency	$4$	$6$	$8$	$5$	$2$

The mean deviation about the mean for the data $4, 7, 8, 9, 10, 12, 13, 17$ is

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