The mean deviation of the numbers 3, 4, 5, 6, | vedclass

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Question

(B) First,calculate the arithmetic mean $(\bar{x})$:$\bar{x} = \frac{3 + 4 + 5 + 6 + 7}{5} = \frac{25}{5} = 5$Next,calculate the mean deviation about

Vedclass · Accepted Answer

$1.2$

Vedclass · Answer

(B) First,calculate the arithmetic mean $(\bar{x})$:$\bar{x} = \frac{3 + 4 + 5 + 6 + 7}{5} = \frac{25}{5} = 5$Next,calculate the mean deviation about the mean using the formula:$	ext{Mean Deviation} = \frac{\sum |x_i - \bar{x}|}{n}$Substitute the values:$= \frac{|3 - 5| + |4 - 5| + |5 - 5| + |6 - 5| + |7 - 5|}{5}$$= \frac{|-2| + |-1| + |0| + |1| + |2|}{5}$$= \frac{2 + 1 + 0 + 1 + 2}{5} = \frac{6}{5} = 1.2$

Class interval	$0-6$	$6-12$	$12-18$	$18-24$	$24-30$
Frequency	$4$	$5$	$3$	$6$	$2$

$x_i$	$5$	$7$	$9$	$10$	$12$	$15$
$f_i$	$8$	$6$	$2$	$2$	$2$	$6$

The mean deviation of the numbers $3, 4, 5, 6, 7$ is

Similar Questions

The mean deviation about the median of the numbers $3x, 6x, 9x, \ldots, 81x$ is $91$. Then $|x| = $

Calculate the mean deviation from the median of the following data:
Class interval $0-6$ $6-12$ $12-18$ $18-24$ $24-30$
Frequency $4$ $5$ $3$ $6$ $2$

What is the mean deviation of a frequency distribution equal to?

The mean deviation about the mean for the data:

$x_i$ $5$ $7$ $9$ $10$ $12$ $15$

$f_i$ $8$ $6$ $2$ $2$ $2$ $6$

is equal to: (in /$13$)

For a frequency distribution,the mean deviation from the mean is computed by:

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