For a frequency distribution,the mean deviation from the mean is computed by:
- A$M.D. = \frac{\sum d}{\sum f}$
- B$M.D. = \frac{\sum fd}{\sum f}$
- C$M.D. = \frac{\sum f|d|}{\sum f}$
- D$M.D. = \frac{\sum f}{\sum f|d|}$
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Similar Questions
The mean deviation from the median of the data $16, 22, 3, 14, 5, 10, 8, 6, 11, 4$ is
The mean deviation about the median for the observations $70, 42, 63, 34, 44, 54, 55, 46, 38, 48$ is:
Medium
View SolutionFind the mean deviation about the mean for the data $38, 70, 48, 40, 42, 55, 63, 46, 54, 44$.
Medium
View SolutionThe mean deviation about the mean for the following data is:
$\text{Marks obtained}$ $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $\text{Number of Boys}$ $6$ $8$ $10$ $4$ $2$
| $\text{Marks obtained}$ | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
| $\text{Number of Boys}$ | $6$ | $8$ | $10$ | $4$ | $2$ |
Find the mean deviation about the mean for the following data:
Income per day Number of persons $0-100$ $4$ $100-200$ $8$ $200-300$ $9$ $300-400$ $10$ $400-500$ $7$ $500-600$ $5$ $600-700$ $4$ $700-800$ $3$
| Income per day | Number of persons |
| $0-100$ | $4$ |
| $100-200$ | $8$ |
| $200-300$ | $9$ |
| $300-400$ | $10$ |
| $400-500$ | $7$ |
| $500-600$ | $5$ |
| $600-700$ | $4$ |
| $700-800$ | $3$ |
Medium
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