Find the mean deviation about the mean for th | vedclass

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(A) The given data is $38, 70, 48, 40, 42, 55, 63, 46, 54, 44$.First,calculate the mean $(\bar{x})$:$\bar{x} = \frac{38+70+48+40+42+55+63+46+54+44}{10

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$8.4$

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(A) The given data is $38, 70, 48, 40, 42, 55, 63, 46, 54, 44$.First,calculate the mean $(\bar{x})$:$\bar{x} = \frac{38+70+48+40+42+55+63+46+54+44}{10} = \frac{500}{10} = 50$.Next,find the absolute deviations $|x_i - \bar{x}|$ for each observation:$|38-50| = 12$$|70-50| = 20$$|48-50| = 2$$|40-50| = 10$$|42-50| = 8$$|55-50| = 5$$|63-50| = 13$$|46-50| = 4$$|54-50| = 4$$|44-50| = 6$The sum of absolute deviations is $12 + 20 + 2 + 10 + 8 + 5 + 13 + 4 + 4 + 6 = 84$.The mean deviation about the mean is $\frac{\sum |x_i - \bar{x}|}{n} = \frac{84}{10} = 8.4$.

$x_i$	$6$	$12$	$18$	$24$	$30$	$36$	$42$
$f_i$	$4$	$7$	$9$	$18$	$15$	$10$	$5$

$\text{Marks obtained}$	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
$\text{Number of Boys}$	$6$	$8$	$10$	$4$	$2$

Find the mean deviation about the mean for the data $38, 70, 48, 40, 42, 55, 63, 46, 54, 44$.

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