The mean free path of electrons in a metal is $4 \times 10^{-8} \;m$. The electric field which can give on an average $2 \;eV$ energy to an electron in the metal will be in units of $V/m$.

  • A
    $8 \times 10^7$
  • B
    $5 \times 10^7$
  • C
    $5 \times 10^{-11}$
  • D
    $8 \times 10^{-11}$

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