The modulation frequency of an AM radio stati | vedclass

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(D) Given,modulation frequency $(f_m)$ = $250\, kHz$.It is given that $f_m$ is $10\%$ of the carrier frequency $(f_c)$.So,$250\, kHz = 0.10 	imes f_c

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$2000$

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(D) Given,modulation frequency $(f_m)$ = $250\, kHz$.It is given that $f_m$ is $10\%$ of the carrier frequency $(f_c)$.So,$250\, kHz = 0.10 	imes f_c$.Therefore,$f_c = 2500\, kHz$.To avoid interference,the minimum frequency separation between two $AM$ stations must be $2 	imes f_m = 2 	imes 250\, kHz = 500\, kHz$.Thus,the next available broadcast frequency should be $f_c + 500\, kHz = 2500\, kHz + 500\, kHz = 3000\, kHz$ or $f_c - 500\, kHz = 2000\, kHz$.Comparing with the given options,$2000\, kHz$ is the correct choice.

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