The molar conductivities at infinite dilution for sodium acetate,$HCl$ and $NaCl$ are $91 \ S \ cm^2 \ mol^{-1}$,$425.9 \ S \ cm^2 \ mol^{-1}$ and $126.4 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of acetic acid at infinite dilution is

  • A
    $39.05 \ S \ cm^2 \ mol^{-1}$
  • B
    $530.9 \ S \ cm^2 \ mol^{-1}$
  • C
    $390.5 \ S \ cm^2 \ mol^{-1}$
  • D
    $930.5 \ S \ cm^2 \ mol^{-1}$

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If the values of $\Lambda_{\infty}$ of $NH_4Cl$,$NaOH$ and $NaCl$ are $130$,$217$ and $109 \ ohm^{-1} \ cm^2 \ equiv^{-1}$ respectively,the $\Lambda_{\infty}$ of $NH_4OH$ in $ohm^{-1} \ cm^2 \ equiv^{-1}$ is:

If the molar conductivity of a solution is $1.26 \times 10^{2} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$ and its molarity is $0.01 \ M$,what will be its specific conductivity?

The specific conductance $(\kappa)$ of $0.02 \ M$ aqueous acetic acid solution at $298 \ K$ is $1.65 \times 10^{-4} \ S \ cm^{-1}$. The degree of dissociation of acetic acid is [Given equivalent conductance at infinite dilution of $H^{+} = 349.1 \ S \ cm^{2} \ mol^{-1}$ and $CH_{3}COO^{-} = 40.9 \ S \ cm^{2} \ mol^{-1}$]

The resistance of a conductivity cell filled with $0.1 \ M$ electrolyte solution is $100 \ \Omega$. The conductivity of this solution is $1.29 \ S \ m^{-1}$. If the resistance of the same cell filled with $0.02 \ M$ solution is $520 \ \Omega$,what is the molar conductivity of the $0.02 \ M$ solution?

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The conductivity of a centimolar solution of $KCl$ at $25^{\circ} C$ is $0.0210 \, \Omega^{-1} cm^{-1}$ and the resistance of the cell containing the solution at $25^{\circ} C$ is $60 \, \Omega$. The value of the cell constant is $......... \, cm^{-1}$.

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