The molar conductivity of $0.01 \text{ M}$ monobasic acid at $25 \text{ }^\circ\text{C}$ is $15 \text{ ohm}^{-1} \text{cm}^2 \text{mol}^{-1}$. The molar conductivity of the same acid at infinite dilution is $375 \text{ ohm}^{-1} \text{cm}^2 \text{mol}^{-1}$. Calculate $[H^+]$ in solution.
- A$4 \times 10^{-4} \text{ M}$
- B$5 \times 10^{-4} \text{ M}$
- C$2 \times 10^{-4} \text{ M}$
- D$3 \times 10^{-4} \text{ M}$
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