The molecular formula of tetraammineaquachlor | vedclass

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(B) The $IUPAC$ name is tetraammineaquachloridocobalt$(III)$ chloride.$1$. The central metal ion is $Co$ with an oxidation state of $+3$.$2$. The liga

Vedclass · Accepted Answer

$[Co(NH_3)_4(H_2O)Cl]Cl_2$

Vedclass · Answer

(B) The $IUPAC$ name is tetraammineaquachloridocobalt$(III)$ chloride.$1$. The central metal ion is $Co$ with an oxidation state of $+3$.$2$. The ligands are four ammine $(NH_3)$,one aqua $(H_2O)$,and one chlorido $(Cl^-)$ group inside the coordination sphere.$3$. The total charge of the coordination sphere is calculated as: $x + 4(0) + 1(0) + 1(-1) = +3$,which gives $x = +4$. However,the oxidation state is $+3$,so the sphere charge is $3 - 1 = +2$.$4$. To balance the $+2$ charge of the complex $[Co(NH_3)_4(H_2O)Cl]^{2+}$,two chloride ions $(Cl^-)$ are required outside the coordination sphere.$5$. Thus,the formula is $[Co(NH_3)_4(H_2O)Cl]Cl_2$.

The molecular formula of tetraammineaquachloridocobalt$(III)$ chloride is . . . . . . .

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Write the formulas for the following coordination compounds:
$(a)$ Tetraammineaquachloridocobalt $(III)$ chloride
$(b)$ Potassium tetrahydroxidozincate $(II)$
$(c)$ Potassium trioxalatoaluminate $(III)$
$(d)$ Dichloridobis(ethane$-1,2-$diamine)cobalt $(III)$
$(e)$ Tetracarbonylnickel $(0)$

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