The moment of linear momentum is called:

$A$ particle is rotating in a circle with uniform speed as shown. The angular momentum of the particle with respect to the origin is .........

Two cars $A$ and $B$ each of mass $10^3 \text{ kg}$ are moving on parallel tracks separated by a distance of $10 \text{ m}$, in the same direction with speeds $72 \text{ km/h}$ and $36 \text{ km/h}$. The magnitude of angular momentum of car $A$ with respect to car $B$ is . . . . . . $\text{J} \cdot \text{s}$.

$A$ particle starts from the point $(0, 8) \, m$ and moves with a uniform velocity of $\vec{v} = 3 \hat{i} \, m/s$. What is the angular momentum of the particle about the origin after $5 \, s$ (mass of the particle is $1 \, kg$)?

$A$ mass $M$ hangs on a massless rod of length $l$ which rotates at a constant angular frequency $\omega$. The mass $M$ moves with steady speed in a circular path of constant radius $r$. The angular momentum of $M$ about point $A$ is $L_A$,which lies in the positive $z$-direction,and the angular momentum of $M$ about point $B$ is $L_B$. Which of the following statements is correct for this system?

$A$ particle of mass $m$ moves with a constant velocity $\vec{v}$ in the $X-Y$ plane. Its angular momentum with respect to the origin is: