The momentum of a photon with energy 20 , eV | vedclass

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(B) The energy of a photon is given by $E = pc$,where $p$ is the momentum and $c$ is the speed of light.Thus,the momentum $p = E/c$.Given $E = 20 \, e

Vedclass · Accepted Answer

$10.66 	imes 10^{-27} \, kg \cdot m/s$

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(B) The energy of a photon is given by $E = pc$,where $p$ is the momentum and $c$ is the speed of light.Thus,the momentum $p = E/c$.Given $E = 20 \, eV = 20 	imes 1.6 	imes 10^{-19} \, J = 3.2 	imes 10^{-18} \, J$.The speed of light $c = 3 	imes 10^8 \, m/s$.Substituting these values:$p = \frac{3.2 	imes 10^{-18}}{3 	imes 10^8} \, kg \cdot m/s$.$p = 1.066 	imes 10^{-26} \, kg \cdot m/s = 10.66 	imes 10^{-27} \, kg \cdot m/s$.Therefore,the correct option is $B$.

The momentum of a photon with energy $20 \, eV$ is

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