The most reactive molecules towards SN^1 reac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The rate of $SN^1$ reaction depends on the stability of the carbocation intermediate formed after the departure of the leaving group $(Cl^-)$. The

Vedclass · Accepted Answer

$(I), (IV)$ and $(VI)$

Vedclass · Answer

(A) The rate of $SN^1$ reaction depends on the stability of the carbocation intermediate formed after the departure of the leaving group $(Cl^-)$. The more stable the carbocation,the faster the $SN^1$ reaction.$(I)$ forms a highly stable carbocation due to resonance stabilization by two $p$-methoxyphenyl groups. The $+R$ effect of the methoxy group significantly stabilizes the positive charge.$(IV)$ is $tert$-butyl chloride,which forms a stable tertiary carbocation.$(VI)$ is $2$-chloro-$2$-phenylpropane,which forms a tertiary carbocation stabilized by resonance with the phenyl ring and the $+I$ effect of methyl groups.$(II)$ is a primary alkyl halide (unstable carbocation).$(III)$ is a primary benzylic halide with a strong electron-withdrawing $-NO_2$ group,which destabilizes the carbocation.$(V)$ is chlorobenzene,which does not undergo $SN^1$ reaction easily due to partial double bond character of the $C-Cl$ bond and the instability of the phenyl cation.Therefore,$(I), (IV)$ and $(VI)$ are the most reactive towards $SN^1$ reaction.

The most reactive molecules towards $SN^1$ reaction are:

Similar Questions

The major product obtained in the following reaction is $C_2H_5ONa + (CH_3)_3C-Cl \rightarrow$

The reactivity of the halogen atom is minimum in:

$CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{Alc. KOH} X$ (major)
$CH_3-CH_2-CH(NMe_3^+) - CH_3 \xrightarrow{EtONa, \Delta} Y$ (major)
Product $(X)$ and $(Y)$ respectively are:

Identify the chiral molecule from the following:

Which one of the following has the highest boiling point?

Vedclass Test Series

Exam Paper Generator

Online Exam Module