The most stable carbocation among the followi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of carbocations is determined by the inductive effect $(+I)$ and hyperconjugation (number of $\alpha-H$ atoms).$1$. $(CH_{3})_{3}C^{

Vedclass · Accepted Answer

$(CH_{3})_{3}C^{+}$

Vedclass · Answer

(A) The stability of carbocations is determined by the inductive effect $(+I)$ and hyperconjugation (number of $\alpha-H$ atoms).$1$. $(CH_{3})_{3}C^{+}$ is a tertiary $(3^{\circ})$ carbocation with $9$ $\alpha-H$ atoms.$2$. $CH_{3}CH_{2}CH^{+}CH_{2}CH_{3}$ is a secondary $(2^{\circ})$ carbocation with $4$ $\alpha-H$ atoms.$3$. $CH_{3}CH^{+}CH_{2}CH_{2}CH_{3}$ is a secondary $(2^{\circ})$ carbocation with $3$ $\alpha-H$ atoms.$4$. $CH_{3}CH_{2}CH_{2}^{+}$ is a primary $(1^{\circ})$ carbocation with $2$ $\alpha-H$ atoms.Since the stability order is $3^{\circ} > 2^{\circ} > 1^{\circ}$, the tertiary carbocation $(CH_{3})_{3}C^{+}$ is the most stable.

The most stable carbocation among the following is:

Similar Questions

Arrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below:

Among the given species,which carbocations are resonance stabilized?

Which of the following carbanions is the least stable?

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

The correct order of relative stability for the given free radicals is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module