(A) The induced electromotive force $(e_2)$ in the secondary circuit is given by the formula: $e_2 = M \frac{di_1}{dt}$.Since the secondary circuit ha

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(A) The induced electromotive force $(e_2)$ in the secondary circuit is given by the formula: $e_2 = M \frac{di_1}{dt}$.Since the secondary circuit has a resistance $R_2$,the induced current $i_2$ is given by $i_2 = \frac{e_2}{R_2}$,which implies $e_2 = i_2 R_2$.Equating the two expressions for $e_2$,we get: $i_2 R_2 = M \frac{di_1}{dt}$.Given values are $M = 0.5 \, H$,$R_2 = 5 \, \Omega$,and $i_2 = 0.4 \, A$.Substituting these values into the equation: $0.4 \times 5 = 0.5 \times \frac{di_1}{dt}$.$2.0 = 0.5 \times \frac{di_1}{dt}$.$\frac{di_1}{dt} = \frac{2.0}{0.5} = 4 \, A/s$.

Class 12 Physics Electromagnetic Induction Mutual Induction

Medium

The mutual inductance between a primary and secondary circuit is $0.5 \, H$. The resistances of the primary and the secondary circuits are $20 \, \Omega$ and $5 \, \Omega$ respectively. To generate a current of $0.4 \, A$ in the secondary,the current in the primary must be changed at the rate of . . . . . . $A/s$.

A
$4$
B
$16$
C
$1.6$
D
$8$

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Chapter

Electromagnetic Induction

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Mutual Induction

$A$ small square loop of side $a$ and one turn is placed inside a larger square loop of side $b$ and one turn $(b \gg a)$. The two loops are coplanar with their centres coinciding. If a current $I$ is passed in the square loop of side $b$,then the coefficient of mutual inductance between the two loops is

DifficultJEE MAIN 2021

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When magnetic flux changes from $6.5 \times 10^{-2} \ Wb$ to $11 \times 10^{-2} \ Wb$ and the change in current is $0.03 \ A$,the coefficient of mutual inductance will be: (in $H$)

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$A$ small circular loop of wire of radius $a$ is located at the centre of a much larger circular wire loop of radius $b$. The two loops are in the same plane. The outer loop of radius $b$ carries an alternating current $I = I_0 \cos (\omega t)$. The emf induced in the smaller inner loop is nearly

DifficultJEE MAIN 2017

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The mutual inductance of an induction coil is $5\,H$. In the primary coil,the current reduces from $5\,A$ to zero in $10^{-3}\,s$. What is the induced emf in the secondary coil in $V$?

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In a transformer, the coefficient of mutual inductance between the primary and the secondary coil is $0.2 \, H$. When the current changes by $5 \, A/s$ in the primary, the induced $e.m.f.$ in the secondary will be......$V$

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When magnetic flux changes from $6.5 \times 10^{-2} \ Wb$ to $11 \times 10^{-2} \ Wb$ and the change in current is $0.03 \ A$,the coefficient of mutual inductance will be: (in $H$)

$A$ small circular loop of wire of radius $a$ is located at the centre of a much larger circular wire loop of radius $b$. The two loops are in the same plane. The outer loop of radius $b$ carries an alternating current $I = I_0 \cos (\omega t)$. The emf induced in the smaller inner loop is nearly

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