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(B) The addition of $HI$ to alkenes in the presence of peroxide does not follow the anti-Markovnikov rule because the free radical mechanism is not fe

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$2-$Iodopropane

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(B) The addition of $HI$ to alkenes in the presence of peroxide does not follow the anti-Markovnikov rule because the free radical mechanism is not feasible for $HI$ due to the endothermic nature of the iodine radical formation step.Therefore,the reaction follows the Markovnikov addition rule,where the electrophile $H^+$ adds to the carbon with more hydrogen atoms.$CH_3-CH=CH_2 + HI \rightarrow CH_3-CH(I)-CH_3$The product formed is $2-$iodopropane (also known as isopropyl iodide).

The name of the product obtained by the addition of $HI$ to propene in the presence of a peroxide catalyst is:

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