The nature of a graph drawn for a freely fall | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a freely falling body, the equation of motion for velocity is given by $v = u + gt$. Since the initial speed $u = 0$, the equation becomes $v

Vedclass · Accepted Answer

a straight line passing through the origin.

Vedclass · Answer

(B) For a freely falling body, the equation of motion for velocity is given by $v = u + gt$. Since the initial speed $u = 0$, the equation becomes $v = gt$. Here, $g$ is the acceleration due to gravity, which is a constant ($g \approx 9.8 \ m/s^2$ or $10 \ m/s^2$). This equation $v = gt$ is of the form $y = mx$, where $y$ represents speed, $x$ represents time, and $m = g$ is the slope. Since there is no constant term (intercept), the graph is a straight line passing through the origin $(0, 0)$. Therefore, the correct option is $B$.

The nature of a graph drawn for a freely falling body with time on the $x$-axis and speed on the $y$-axis is (Assuming initial speed to be zero.)

Similar Questions

$A$ food packet is dropped from a helicopter rising up with a velocity of $4 \, ms^{-1}$. The velocity of the packet after $3 \, s$ will be ....... $ms^{-1}$. (in $.4$)

$A$ ball is thrown upwards. Its height varies with time as shown in the graph. If the acceleration due to gravity is $g = 7.5\, m/s^2$,then the height $h$ is.........$m$.

$A$ $0.4\,kg$ mass takes $8\,s$ to reach the ground when dropped from a certain height $P$ above the surface of the Earth. The loss of potential energy in the last second of the fall is $..............J$. [Take $g = 10\,m/s^2$]

What is the speed-time graph for a ball thrown vertically upwards? (Neglect air resistance)

Vedclass Test Series

Exam Paper Generator

Online Exam Module