The negation of the expression $q \vee ((\sim q) \wedge p)$ is equivalent to

If $(p \wedge \sim q) \wedge (p \wedge r) \rightarrow \sim p \vee q$ is false,then the truth values of $p, q$ and $r$ are respectively

If the truth value of the compound statement $[(p \leftrightarrow q) \land (q \to r) \land \sim r] \to (p \land \sim q)$ is false, then the truth values of the statement patterns $(p \to q) \leftrightarrow (q \to r)$ and $\sim (p \lor r) \to (q \land p)$ are, respectively ...

Let $A, B, C$ and $D$ be four non-empty sets. The contrapositive statement of "If $A \subseteq B$ and $B \subseteq D,$ then $A \subseteq C$" is

The contrapositive of the statement: 'If a function $f$ is differentiable at $a$,then it is also continuous at $a$',is

If $p$, $q$, $r$ are simple propositions with truth values $T$, $F$, $T$ respectively, then which of the following is not a true statement?