The negation of the inverse of the statement | vedclass

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(B) Step $1$: The given statement is $S = \sim p \lor q$.Step $2$: The inverse of a conditional statement $p 	o q$ is $\sim p 	o \sim q$. However, f

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$p \land q$

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(B) Step $1$: The given statement is $S = \sim p \lor q$.Step $2$: The inverse of a conditional statement $p 	o q$ is $\sim p 	o \sim q$. However, for a general statement $S$, the inverse is defined as $\sim S$. Thus, the inverse of $\sim p \lor q$ is $\sim (\sim p \lor q)$.Step $3$: Using De Morgan's Law, $\sim (\sim p \lor q) = \sim (\sim p) \land \sim q = p \land \sim q$.Step $4$: The negation of this inverse is $\sim (p \land \sim q)$.Step $5$: Applying De Morgan's Law again, $\sim (p \land \sim q) = \sim p \lor \sim (\sim q) = \sim p \lor q$.Wait, re-evaluating the standard definition: The inverse of $p 	o q$ is $\sim p 	o \sim q$. The statement $\sim p \lor q$ is logically equivalent to $p 	o q$. Step $6$: The inverse of $p 	o q$ is $\sim p 	o \sim q$, which is equivalent to $\sim (\sim p) \lor \sim q = p \lor \sim q$.Step $7$: The negation of $p \lor \sim q$ is $\sim (p \lor \sim q) = \sim p \land \sim (\sim q) = \sim p \land q$.

The negation of the inverse of the statement $∼ p \lor q$ is...

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