The nuclear reaction ^2H + ^2H to ^4He (mass | vedclass

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Question

(A) The reaction $^2H + ^2H 	o ^4He$ involves the combination of two light nuclei to form a heavier nucleus,which is a nuclear fusion reaction.Total

Vedclass · Accepted Answer

Fusion reaction releasing $24 \,MeV$ energy

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(A) The reaction $^2H + ^2H 	o ^4He$ involves the combination of two light nuclei to form a heavier nucleus,which is a nuclear fusion reaction.Total mass of reactants $= 2 	imes 2.0141 \,amu = 4.0282 \,amu$.Total mass of products $= 4.0024 \,amu$.Mass defect $\Delta m = 	ext{Mass of reactants} - 	ext{Mass of products} = 4.0282 \,amu - 4.0024 \,amu = 0.0258 \,amu$.Energy released $E = \Delta m 	imes 931 \,MeV/amu = 0.0258 	imes 931 \approx 24 \,MeV$.Since energy is released,it is an exothermic fusion reaction.

The nuclear reaction $^2H + ^2H \to ^4He$ (mass of deuteron $= 2.0141 \,amu$ and mass of $He = 4.0024 \,amu$) is

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