The number of 3c-2e bond and 2c-2e bond prese | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The structure of $Be_2(CH_3)_4$ is a dimer where two $Be$ atoms are bridged by two methyl groups.In this structure,there are two $3c-2e$ (three-ce

Vedclass · Accepted Answer

$2, 14$

Vedclass · Answer

(B) The structure of $Be_2(CH_3)_4$ is a dimer where two $Be$ atoms are bridged by two methyl groups.In this structure,there are two $3c-2e$ (three-center two-electron) bonds formed by the bridging $Be-C-Be$ units.Each $Be$ atom is also bonded to one terminal methyl group via a $2c-2e$ bond.Additionally,each of the four methyl groups contains three $C-H$ bonds,which are $2c-2e$ bonds.Total $2c-2e$ bonds = $2$ (terminal $Be-C$ bonds) + $4 	imes 3$ ($C-H$ bonds) = $2 + 12 = 14$.Thus,the number of $3c-2e$ bonds is $2$ and the number of $2c-2e$ bonds is $14$.

The number of $3c-2e$ bond and $2c-2e$ bond present in $Be_2(CH_3)_4$ are $ . . . . . . $ and $ . . . . . . $ respectively.

Similar Questions

The number of molecules from the following which contain only two lone pairs of electrons is $........$.
$H_2O, N_2, CO, XeF_4, NH_3, NO, CO_2, F_2$

What is the number of $\sigma$ and $\pi$ bonds in tetracyanoethylene?

Which one of the following conversions involves a change in both hybridisation and shape?

Arrange the bonds in order of increasing ionic character in the molecules: $LiF, K_2O, N_2, SO_2$ and $ClF_3$.

Which of the following order is incorrect?

Vedclass Test Series

Exam Paper Generator

Online Exam Module