The number of pi-bonds in the product formed | vedclass

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(B) The reaction of acetylene $(CH \equiv CH)$ with water in the presence of dilute $H_2SO_4$ and $HgSO_4$ is a hydration reaction.$CH \equiv CH + H_2

Vedclass · Accepted Answer

$1$

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(B) The reaction of acetylene $(CH \equiv CH)$ with water in the presence of dilute $H_2SO_4$ and $HgSO_4$ is a hydration reaction.$CH \equiv CH + H_2O$ $\xrightarrow{dil. H_2SO_4, HgSO_4} [CH_2=CH-OH]$ $\rightarrow CH_3-CHO$.The final product formed is acetaldehyde $(CH_3-CHO)$.In the structure of acetaldehyde $(CH_3-C(=O)H)$,there is one $C=O$ double bond,which consists of $1$ $\sigma$-bond and $1$ $\pi$-bond.Therefore,the number of $\pi$-bonds is $1$.

The number of $\pi$-bonds in the product formed by passing acetylene through dilute sulphuric acid containing mercuric sulphate is

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