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(B) $1$. The reaction of cyclohexyl methyl ketone with $PCl_5$ at $0^{\circ}C$ results in the formation of a gem-dichloride,specifically $1,1$-dichlor

Vedclass · Accepted Answer

Ethynylcyclohexane

Vedclass · Answer

(B) $1$. The reaction of cyclohexyl methyl ketone with $PCl_5$ at $0^{\circ}C$ results in the formation of a gem-dichloride,specifically $1,1$-dichloroethylcyclohexane,which is product $(A)$.$2$. The subsequent treatment of $(A)$ with $3 \ NaNH_2$ in mineral oil followed by an acidic workup $(H^{\oplus})$ leads to a double dehydrohalogenation reaction.$3$. The $1,1$-dichloroethylcyclohexane undergoes elimination of two molecules of $HCl$ to form the terminal alkyne,ethynylcyclohexane,which is product $(B)$.

The product $(B)$ is:

Similar Questions

$CH \equiv CH + CO + H_2O \xrightarrow{Ni(CO)_4} \text{Product}$. For this reaction,which statement is false?

The product $(C)$ of the above reaction is:
Maleic anhydride $\xrightarrow{H_3O^+}$ $(A)$ $\xrightarrow{NaOH}$ $(B)$ $\xrightarrow{\text{Kolbe electrolysis}}$ $(C)$

The product obtained in this reaction is:

The reaction sequence is given as:
$CH_3-CH=CH-CH_3$ $\xrightarrow{Br_2/CCl_4} \text{Intermediate}$ $\xrightarrow[(ii) NaNH_2]{(i) alc. KOH} (A)$
Product $(A)$ is:

The product $(K)$ of the following reaction is:

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