The product obtained in this reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction involves the terminal alkyne $Ph-C \equiv C-H$ reacting with $I_2$ in the presence of a base (morpholine).$1$. The base (morpholine)

Vedclass · Accepted Answer

$Ph-C \equiv C-I$

Vedclass · Answer

(A) The reaction involves the terminal alkyne $Ph-C \equiv C-H$ reacting with $I_2$ in the presence of a base (morpholine).$1$. The base (morpholine) abstracts the acidic terminal proton from the alkyne to form an acetylide anion: $Ph-C \equiv C^-$.$2$. The acetylide anion then acts as a nucleophile and attacks the iodine molecule $(I-I)$,displacing an iodide ion $(I^-)$.$3$. This results in the formation of the iodoalkyne product: $Ph-C \equiv C-I$.

Similar Questions

Identify the alkyne in the following sequence of reactions:
Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$
Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.

$C_2H_5-C \equiv C-C_2H_5$ $\xrightarrow{Na/liq. NH_3} (A)$ $\xrightarrow{Br_2/CCl_4} (B)$
Which statement is correct regarding product $(B)$?

$C_6H_5-C \equiv C-CH_3 \xrightarrow[H_2SO_4]{HgSO_4, H_2O} A$. The major product $(A)$ is:

Which reagent can be used to distinguish between $1$-butyne and $2$-butyne?

Identify the correct order of acidic strength for the following hydrocarbons:

Vedclass Test Series

Exam Paper Generator

Online Exam Module