The number of P=O and P-P bonds present in th | vedclass

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(A) The reaction of red $P_4$ with alkali (like $NaOH$) produces hypophosphite $(H_2PO_2^-)$ and phosphine $(PH_3)$. The oxoacid formed upon acidifica

Vedclass · Accepted Answer

$2, 1$

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(A) The reaction of red $P_4$ with alkali (like $NaOH$) produces hypophosphite $(H_2PO_2^-)$ and phosphine $(PH_3)$. The oxoacid formed upon acidification is hypophosphorous acid $(H_3PO_2)$.In the structure of $H_3PO_2$,there is one $P=O$ bond,two $P-H$ bonds,and one $P-OH$ bond.However,the question refers to the oxoacid prepared by treating $P_4$ with alkali,which is hypophosphorous acid $(H_3PO_2)$.Wait,let us re-evaluate: The reaction of $P_4$ with $NaOH$ gives $PH_3$ and $NaH_2PO_2$. The acid is $H_3PO_2$. Its structure is $P(=O)(H)_2(OH)$. It has one $P=O$ bond and zero $P-P$ bonds.If the question refers to hypophosphoric acid $(H_4P_2O_6)$,it has one $P-P$ bond and two $P=O$ bonds. But $H_4P_2O_6$ is not prepared by treating $P_4$ with alkali.Given the options,the question likely refers to hypophosphoric acid $(H_4P_2O_6)$,which contains $2$ $P=O$ bonds and $1$ $P-P$ bond. Thus,the correct option is $A$.

The number of $P=O$ and $P-P$ bonds present in the oxoacid of phosphorus,prepared by treating red $P_4$ with alkali,are respectively:

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