The number of d- electrons in Fe^{2+} (Z = 2 | vedclass

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(D) The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^{6} 4s^{0}$. Thus,the number of $d-$ electrons is $6$.$A) \ Fe \ (Z = 26): [Ar] 3d^{6} 4s^{2

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$p-$ electrons in $Cl \ (Z = 17)$

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(D) The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^{6} 4s^{0}$. Thus,the number of $d-$ electrons is $6$.$A) \ Fe \ (Z = 26): [Ar] 3d^{6} 4s^{2}$. Number of $d-$ electrons is $6$.$B) \ Ne \ (Z = 10): 1s^{2} 2s^{2} 2p^{6}$. Number of $p-$ electrons is $6$.$C) \ Mg \ (Z = 12): 1s^{2} 2s^{2} 2p^{6} 3s^{2}$. Total number of $s-$ electrons is $2 + 2 + 2 = 6$.$D) \ Cl \ (Z = 17): 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{5}$. Total number of $p-$ electrons is $6 + 5 = 11$.Since $11 
eq 6$,the number of $p-$ electrons in $Cl$ is not equal to the number of $d-$ electrons in $Fe^{2+}$.

The number of $d-$ electrons in $Fe^{2+} \ (Z = 26)$ is not equal to the number of electrons in which one of the following?

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