The number of all 8-digit odd numbers is | vedclass

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(A) An $8$-digit number is formed by $8$ positions. For the number to be odd,the last digit (units place) must be one of $\{1, 3, 5, 7, 9\}$,which giv

Vedclass · Accepted Answer

$45 	imes 10^6$

Vedclass · Answer

(A) An $8$-digit number is formed by $8$ positions. For the number to be odd,the last digit (units place) must be one of $\{1, 3, 5, 7, 9\}$,which gives $5$ choices. The first digit cannot be $0$,so it has $9$ choices $(\{1, 2, 3, 4, 5, 6, 7, 8, 9\})$. The remaining $6$ positions (from the $2^{nd}$ to the $7^{th}$ digit) can each be filled by any of the $10$ digits $(\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\})$,giving $10^6$ ways. Therefore,the total number of $8$-digit odd numbers is $9 	imes 10^6 	imes 5 = 45 	imes 10^6$.

The number of all $8$-digit odd numbers is

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