The number of anti-bonding electrons present | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The total number of electrons in $O_{2}^{-}$ is $8 + 8 + 1 = 17$.The molecular orbital configuration of $O_{2}^{-}$ is: $\sigma 1s^{2}, \sigma^{*}

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(D) The total number of electrons in $O_{2}^{-}$ is $8 + 8 + 1 = 17$.The molecular orbital configuration of $O_{2}^{-}$ is: $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^{2} = \pi 2p_{y}^{2}, \pi^{*} 2p_{x}^{2} = \pi^{*} 2p_{y}^{1}$.Anti-bonding electrons are those in orbitals denoted with an asterisk $(*)$.Number of anti-bonding electrons $= 2(\sigma^{*} 1s) + 2(\sigma^{*} 2s) + 2(\pi^{*} 2p_{x}) + 1(\pi^{*} 2p_{y}) = 7$.

The number of anti-bonding electrons present in $O_{2}^{-}$ molecular ion is

Similar Questions

Among $KO_2$,$NO_2^-$,$BaO_2$ and $NO_2^+$,an unpaired electron is present in:

The bond order is maximum in

According to $MO$ theory,which of the following lists ranks the nitrogen species in terms of increasing bond order?

Use molecular orbital theory to explain why the $Be_{2}$ molecule does not exist.

Compare the relative stability of the following species and indicate the magnetic properties: $O_2$,$O_2^+$,$O_2^-$ (superoxide),and $O_2^{2-}$ (peroxide).

Vedclass Test Series

Exam Paper Generator

Online Exam Module