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(D) $1$. $[PtCl_2(NH_3)_2]$ is a square planar complex of type $[MA_2B_2]$. It exhibits $2$ geometrical isomers (cis and trans).$2$. $[Ni(CO)_4]$ is a

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$2, 0, 2, 2$

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(D) $1$. $[PtCl_2(NH_3)_2]$ is a square planar complex of type $[MA_2B_2]$. It exhibits $2$ geometrical isomers (cis and trans).$2$. $[Ni(CO)_4]$ is a tetrahedral complex. Tetrahedral complexes do not show geometrical isomerism because all positions are equivalent relative to each other. Thus,it has $0$ geometrical isomers.$3$. $[Ru(H_2O)_3Cl_3]$ is an octahedral complex of type $[MA_3B_3]$. It exhibits $2$ geometrical isomers (facial and meridional).$4$. $[CoCl_2(NH_3)_4]^+$ is an octahedral complex of type $[MA_4B_2]$. It exhibits $2$ geometrical isomers (cis and trans).Therefore,the number of geometrical isomers are $2, 0, 2, 2$ respectively.

The number of geometrical isomers found in the metal complexes $[PtCl_2(NH_3)_2]$,$[Ni(CO)_4]$,$[Ru(H_2O)_3Cl_3]$ and $[CoCl_2(NH_3)_4]^+$ respectively,are :

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