The number of geometrical isomers possible in triamminetrinitrocobalt $(III)$ is $X$ and in trioxalatochromate $(III)$ is $Y$. Then the value of $X+Y$ is $....$
- A$1$
- B$2$
- C$3$
- D$4$
Explore More
Similar Questions
The magnetic moment of ${K_3}[Fe(CN)_6]$ is found to be $1.7 \ B.M.$ How many unpaired electron$(s)$ is/are present per molecule?
Medium
View SolutionWhich isomerism is possible in hexa-ammine cobalt$(III)$ hexa-cyanido chromate$(III)$ complex?
$Ni(CO)_4$ and $[Ni(NH_3)_4]^{2+}$ do not differ in
Difficult
View SolutionThe number of geometrical isomers for $[Co(NH_3)_3(NO_2)_3]$ is ....
Medium
View SolutionMatch the List-$I$ with List-$II$:
List-$I$ (Complex ion) List-$II$ (Calculated spin only magnetic moment $(BM)$) $A$. $[Cr(H_2O)_6]^{2+}$ $I$. $3.87$ $B$. $[Co(H_2O)_6]^{2+}$ $II$. $5.92$ $C$. $[Cu(H_2O)_6]^{2+}$ $III$. $4.90$ $D$. $[Mn(H_2O)_6]^{2+}$ $IV$. $1.73$
Choose the correct answer from the options given below:
| List-$I$ (Complex ion) | List-$II$ (Calculated spin only magnetic moment $(BM)$) |
| $A$. $[Cr(H_2O)_6]^{2+}$ | $I$. $3.87$ |
| $B$. $[Co(H_2O)_6]^{2+}$ | $II$. $5.92$ |
| $C$. $[Cu(H_2O)_6]^{2+}$ | $III$. $4.90$ |
| $D$. $[Mn(H_2O)_6]^{2+}$ | $IV$. $1.73$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2026
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo