The number of hydrogen atoms present in $5.4 \ g$ of urea is : (Given : Molar mass of urea: $60 \ g \ mol^{-1}$, $N_{A} = 6.022 \times 10^{23} \ particles \ mol^{-1}$)
- A$2.168 \times 10^{22}$
- B$2.168 \times 10^{23}$
- C$1.084 \times 10^{22}$
- D$1.084 \times 10^{23}$
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