The number of integers greater than a million | vedclass

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(C) number greater than a million must have $7$ digits. The given digits are $0, 2, 2, 3, 3, 3, 4$.Since the number must be greater than a million,the

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$360$

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(C) number greater than a million must have $7$ digits. The given digits are $0, 2, 2, 3, 3, 3, 4$.Since the number must be greater than a million,the first digit cannot be $0$.Case $1$: First digit is $2$. Remaining digits are $0, 2, 3, 3, 3, 4$. The number of arrangements is $\frac{6!}{3!} = \frac{720}{6} = 120$.Case $2$: First digit is $3$. Remaining digits are $0, 2, 2, 3, 3, 4$. The number of arrangements is $\frac{6!}{2!2!} = \frac{720}{4} = 180$.Case $3$: First digit is $4$. Remaining digits are $0, 2, 2, 3, 3, 3$. The number of arrangements is $\frac{6!}{2!3!} = \frac{720}{12} = 60$.Total numbers = $120 + 180 + 60 = 360$.

The number of integers greater than a million that can be formed using the digits $2, 3, 0, 3, 4, 2, 3$ is

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