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(D) The molecular formula $C_2BrClFI$ corresponds to a haloalkene where each carbon of the double bond is substituted with two different halogens.For

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$6$

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(D) The molecular formula $C_2BrClFI$ corresponds to a haloalkene where each carbon of the double bond is substituted with two different halogens.For a general alkene $C(ab)=C(cd)$,if $a 
eq b$ and $c 
eq d$,the molecule exhibits geometrical isomerism ($E$ and $Z$ forms).In the case of $C_2BrClFI$,we can arrange the four different halogens $(Br, Cl, F, I)$ on the two carbons in different ways.There are $3$ possible structural skeletons based on the relative positions of the halogens: $1$. $Br-C(Cl)=C(F)-I$$2$. $Br-C(F)=C(Cl)-I$$3$. $Br-C(I)=C(Cl)-F$Each of these $3$ structural isomers can exist as a pair of geometrical isomers ($E$ and $Z$).Therefore,the total number of stereoisomers is $3 	imes 2 = 6$.

The number of isomers for the compound with molecular formula $C_2BrClFI$ is

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The number of isomers for the compound with molecular formula $C_2BrClFI$ is

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$CH_2 = CH - CH = CH - CH = CH_2$
How many geometrical isomers are possible for this compound?