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(A) Geometrical isomerism requires restricted rotation about a double bond where each carbon atom of the double bond is attached to two different grou

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$Prop-2-$enoic acid

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(A) Geometrical isomerism requires restricted rotation about a double bond where each carbon atom of the double bond is attached to two different groups.$Prop-2-$enoic acid is $CH_2=CH-COOH$. The terminal carbon $(C_1)$ is attached to two identical hydrogen atoms,so it cannot show geometrical isomerism.$2-$butene $(CH_3-CH=CH-CH_3)$ shows geometrical isomerism ($cis$ and $trans$ forms).$2-$methyl$-2-$butenoic acid $(CH_3-CH=C(CH_3)-COOH)$ shows geometrical isomerism because the $C_3$ carbon is attached to $H$ and $CH_3$,and the $C_2$ carbon is attached to $CH_3$ and $COOH$.$3-$methyl$-2-$pentenoic acid $(CH_3-CH_2-C(CH_3)=CH-COOH)$ shows geometrical isomerism because the $C_2$ carbon is attached to $H$ and $COOH$,and the $C_3$ carbon is attached to $CH_3$ and $CH_2CH_3$.

Which one of the following compounds will not show geometrical isomerism?

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