The number of molecules and moles in 2.8375 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) At $STP$,the molar volume of an ideal gas is $22.7 \ L \ mol^{-1}$.Number of moles of $O_2 = \frac{	ext{Volume at } STP}{22.7 \ L \ mol^{-1}} = \

Vedclass · Accepted Answer

$7.527 	imes 10^{22}$ and $0.125 \ mol$

Vedclass · Answer

(D) At $STP$,the molar volume of an ideal gas is $22.7 \ L \ mol^{-1}$.Number of moles of $O_2 = \frac{	ext{Volume at } STP}{22.7 \ L \ mol^{-1}} = \frac{2.8375 \ L}{22.7 \ L \ mol^{-1}} = 0.125 \ mol$.Number of molecules $= 	ext{Number of moles} 	imes N_A = 0.125 	imes 6.022 	imes 10^{23} \ mol^{-1} = 7.5275 	imes 10^{22}$ molecules.Therefore,the values are $7.527 	imes 10^{22}$ molecules and $0.125 \ mol$.

The number of molecules and moles in $2.8375 \ L$ of $O_2$ at $STP$ are respectively

Similar Questions

Calculate the number of atoms of oxygen present in $176 \ g$ of $CO_2$.

Which one of the following has the same number of atoms as are in $6 \,g$ of $H_2O$?

Weight of $112 \, mL$ of oxygen at $NTP$ on liquefaction would be .............. $g$.

How many oxygen atoms are present in $0.36 \ g$ of a drop of water?

Which has the maximum number of molecules?

Vedclass Test Series

Exam Paper Generator

Online Exam Module