The number of molecules in 16 g of methane i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given mass of methane $(CH_4) = 16 \ g$.Molar mass of $CH_4 = 12 + (4 	imes 1) = 16 \ g/mol$.Moles of $CH_4 = \frac{	ext{Given mass}}{	ext{Mola

Vedclass · Accepted Answer

$6.02 	imes 10^{23}$

Vedclass · Answer

(B) Given mass of methane $(CH_4) = 16 \ g$.Molar mass of $CH_4 = 12 + (4 	imes 1) = 16 \ g/mol$.Moles of $CH_4 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{16 \ g}{16 \ g/mol} = 1 \ mol$.Since $1 \ mol$ of any substance contains $6.022 	imes 10^{23}$ molecules (Avogadro's number),Therefore,$1 \ mol$ of $CH_4$ contains $6.02 	imes 10^{23}$ molecules.

The number of molecules in $16 \ g$ of methane is

Similar Questions

The number of atoms present in a drop of water weighing $1.8 \ g$ is.....

Find the number of molecules present in $70 \text{ g}$ of dinitrogen $(N_2)$.

How many $H$ atoms are present in $0.46 \, g$ of ethanol $[C_2H_5OH]$?

Calculate the total number of electrons present in $1.4 \,g$ of dinitrogen gas.

How many moles of oxygen gas at $STP$ are equivalent to $5.6 \ L$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module