The number of paramagnetic metal complex spec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let us analyze the number of unpaired electrons $(n)$ for each complex:$1.$ $[Co(NH_3)_6]^{3+}: Co^{3+} (3d^6)$,$	ext{NH}_3$ is a strong field li

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(D) Let us analyze the number of unpaired electrons $(n)$ for each complex:$1.$ $[Co(NH_3)_6]^{3+}: Co^{3+} (3d^6)$,$	ext{NH}_3$ is a strong field ligand $(SFL)$ $ightarrow t_{2g}^6 e_g^0, n=0$ (Diamagnetic)$2.$ $[Co(C_2O_4)_3]^{3-}: Co^{3+} (3d^6)$,$	ext{C}_2	ext{O}_4^{2-}$ is a $SFL$ with $Co^{3+} ightarrow t_{2g}^6 e_g^0, n=0$ (Diamagnetic)$3.$ $[MnCl_6]^{3-}: Mn^{3+} (3d^4)$,$	ext{Cl}^{-}$ is a weak field ligand $(WFL)$ $ightarrow t_{2g}^3 e_g^1, n=4$ (Paramagnetic)$4.$ $[Mn(CN)_6]^{3-}: Mn^{3+} (3d^4)$,$	ext{CN}^{-}$ is a $SFL$ $ightarrow t_{2g}^4 e_g^0, n=2$ (Paramagnetic)$5.$ $[CoF_6]^{3-}: Co^{3+} (3d^6)$,$	ext{F}^{-}$ is a $WFL$ $ightarrow t_{2g}^4 e_g^2, n=4$ (Paramagnetic)$6.$ $[Fe(CN)_6]^{3-}: Fe^{3+} (3d^5)$,$	ext{CN}^{-}$ is a $SFL$ $ightarrow t_{2g}^5 e_g^0, n=1$ (Paramagnetic)$7.$ $[FeF_6]^{3-}: Fe^{3+} (3d^5)$,$	ext{F}^{-}$ is a $WFL$ $ightarrow t_{2g}^3 e_g^2, n=5$ (Paramagnetic)The paramagnetic species with the same number of unpaired electrons $(n=4)$ are $[MnCl_6]^{3-}$ and $[CoF_6]^{3-}$.Therefore,the number of such species is $2$.

The number of paramagnetic metal complex species among $[Co(NH_3)_6]^{3+}$,$[Co(C_2O_4)_3]^{3-}$,$[MnCl_6]^{3-}$,$[Mn(CN)_6]^{3-}$,$[CoF_6]^{3-}$,$[Fe(CN)_6]^{3-}$ and $[FeF_6]^{3-}$ with the same number of unpaired electrons is $............$

Similar Questions

There are four complexes of $Ni$. Select the complex(es) which will be attracted by a magnetic field:
$(I) \ [Ni(CN)_4]^{2-}, \ (II) \ [NiCl_4]^{2-}, \ (III) \ [Ni(CO)_4]$
$(IV) \ [Ni(H_2O)_6]^{2+}$

Among the following options,select the option in which each complex in Set-$I$ shows geometrical isomerism and the two complexes in Set-$II$ are ionization isomers of each other.
$[en = H_2N-CH_2-CH_2-NH_2]$

The two compounds pentaamminesulphatocobalt $(III)$ bromide and pentaamminesulphatocobalt $(III)$ chloride represent:

The formula for calculating 'spin only' magnetic moment is

Total number of stereoisomers of $[Co(acac)_2BrCl]^{\ominus}$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module