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Question

(C) The power $P$ emitted by a source is given by the product of the number of photons per second $n$ and the energy of a single photon $E = \frac{hc}

Vedclass · Accepted Answer

$10^{16}$

Vedclass · Answer

(C) The power $P$ emitted by a source is given by the product of the number of photons per second $n$ and the energy of a single photon $E = \frac{hc}{\lambda}$.$P = n \frac{hc}{\lambda} \Rightarrow n = \frac{P \lambda}{hc}$Given: $P = 3.3 	imes 10^{-3} \, W$,$\lambda = 600 	imes 10^{-9} \, m$,$h = 6.6 	imes 10^{-34} \, Js$,and $c = 3 	imes 10^8 \, m/s$.Substituting the values:$n = \frac{3.3 	imes 10^{-3} 	imes 600 	imes 10^{-9}}{6.6 	imes 10^{-34} 	imes 3 	imes 10^8}$$n = \frac{3.3 	imes 600 	imes 10^{-12}}{19.8 	imes 10^{-26}}$$n = \frac{1980 	imes 10^{-12}}{19.8 	imes 10^{-26}} = 100 	imes 10^{14} = 10^{16}$Thus,the number of photons emitted per second is $10^{16}$.

The number of photons per second on an average emitted by a source of monochromatic light of wavelength $600 \, nm$,when it delivers a power of $3.3 \times 10^{-3} \, W$,is: $(h = 6.6 \times 10^{-34} \, Js)$

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