The only alcohol that can be prepared by the | vedclass

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Question

(A) The indirect hydration of alkenes involves the reaction with concentrated $H_2SO_4$ followed by hydrolysis.$CH_2=CH_2 + H_2SO_4 	o CH_3-CH_2-HSO_

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Ethyl alcohol

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(A) The indirect hydration of alkenes involves the reaction with concentrated $H_2SO_4$ followed by hydrolysis.$CH_2=CH_2 + H_2SO_4 	o CH_3-CH_2-HSO_4 \xrightarrow{H_2O, \Delta} CH_3-CH_2OH + H_2SO_4$Since the addition of $H_2SO_4$ to alkenes follows Markownikoff's rule,the hydrogen atom attaches to the carbon with more hydrogen atoms,and the $-HSO_4$ group attaches to the more substituted carbon.For ethene $(CH_2=CH_2)$,this results in the formation of ethanol $(CH_3-CH_2OH)$.For higher alkenes,this method typically yields secondary or tertiary alcohols. Therefore,ethyl alcohol is the only primary alcohol that can be prepared by this method.

The only alcohol that can be prepared by the indirect hydration of alkene is

Similar Questions

Show how the following alcohols can be prepared by the reaction of a suitable Grignard reagent with methanal:
$(i)$ $C_6H_5CH_2OH$
$(ii)$ $CH_3CH_2CH(CH_3)CH_2OH$

Which of the following compounds will form a $2^o$ alcohol when treated with a $\text{Grignard reagent}$ followed by hydrolysis?

The reagent $X$ in the reaction sequence: $(CH_3)_3C-CH=CH_2$ $\xrightarrow[THF]{X} Y$ $\xrightarrow[NaOH]{NaBH_4} (CH_3)_3C-CH(OH)-CH_3$ is:

What are $X$ and $Y$ in the following reactions?
$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$
$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$

Propan-$1$-ol can be prepared from propene by:

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